A 72 kg skier leaves the end of a ski-jump ramp with a velocity of 24 m/s directed 25◦ above the horizontal. The skier returns to the ground at a point that is 14 m below the end of the ramp with a total speed of 22 m/s.

(a) What is the rate at which the gravitational force does work on the skier at the moment when he leaves
the ramp?

(b) With what total speed would he have landed if there were no air drag?

(c) What was the work done on the skier by the air drag?

I think I was able to do part (c) by letting 1/2(m)(v2^2-v1^2) + mgh, Got a large number but it seems correct. How do you do a and b!??!