A 72- kg ice hockey player standing on a frictionless sheet of ice throws a 5.6- kg bowling ball horizontally with a speed of 3.9 m/s. With what speed does the hockey player recoil?

Answer 1

momentum before = 0
momentum after = 0
0 = 72 v + 5.6 * 3.9
v = -.303
recoils at .303 m/s