A 71.1 kg man steps out a window and falls (from rest) 1.24 m to a sidewalk. What is his speed just before his feet strike the pavement?

Answer 1

(1/2) m v^2 = m g h
m cancels of course (Galileo)

v = sqrt (2 g h)
remember that

v = sqrt (2*9.81*1.24)
v = 4.93 m/s