To model the number of liters of water in the tank after \( m \) minutes, we can use the function:
\[ n(m) = 700 - 12.5m \]
This represents the initial amount of water (700 liters) minus the water drained after \( m \) minutes at a rate of 12.5 liters per minute.
Now, let's analyze the options:
A. \( n(0) = 0 \)
- False. At \( m = 0 \), \( n(0) = 700 - 12.5(0) = 700 \).
B. \( n(56) = 0 \)
- True. At \( m = 56 \), \( n(56) = 700 - 12.5(56) = 700 - 700 = 0 \).
C. \( n(0) = 56 \)
- False. As calculated above, \( n(0) = 700 \).
D. \( n(0) = 700 \)
- True. As calculated, \( n(0) = 700 \).
E. \( n(700) = 0 \)
- False. At \( m = 700 \), \( n(700) = 700 - 12.5(700) = 700 - 8750 = -8150\) (which is not applicable since the tank cannot have negative water).
F. \( n(56) = 700 \)
- False. As calculated, \( n(56) = 0 \).
Thus, the true statements are:
- B. \( n(56) = 0 \)
- D. \( n(0) = 700 \)