A 7.77 kg pumpkin falls from a height of 12.3m. It hits the ground and comes to an abrupt stop in about 444 ms. What is the average force imparted by the ground (aka 'Normal Force') on the pumpkin?

Answer 1

1/2 m v^2 = m g h

v = √(2 g h)

f = m a

mass is 7.77 kg

acceleration is ... √(2 g h) / .444 s

Answer 2

iahd