You end up with 25.4 g Fe2O3.
25.4g Fe2O3 x (2*atomic mass Fe/molar mass Fe2O3) = mass Fe.
Piecemeal it's done this way.
mols Fe = 25.4 g/molar mass Fe2O3.
Since there are 2 mols Fe for every mole Fe2O3, then mols Fe = twice mols Fe2O3.
Then g Fe = mols Fe x atomic mass Fe.
A 7.7 g sample of iron ore is treated as follows.
The iron in the sample is all converted by a
series of chemical reactions to Fe2O3. The
mass of Fe2O3 is measured to be 25.4 g. What
was the mass of iron in the sample of ore?
Answer in units of g.
1 answer