That is correct. Now you have to figure the horizontal forces, they have to sum to zero. You have the wall force, and you have the force of friction on the ground.
Try this: Sum moments about the base, and find wall force in terms of height h of the man. Then ground fricton has to equal that, and you can solve then for h.
A 7.68 m, 132 kg uniform ladder rests against a smooth wall. The coefficient of static fric- tion between the ladder and the ground is 0.642, and the ladder makes a 48.4◦ angle with the ground.
How far up the ladder can a 528 kg person climb before the ladder begins to slip? The acceleration of gravity is 9.8 m/s2 .
Answer in units of m
I have tried to find normal force:
I got the weights of the person(5174N) and the ladder(1293.6N). And then that answer would be the force of floor on ladder.
2 answers
Horizontal force: i tried to do 7.68cos 48.4 but maybe I should get the cosine components of the weights.
2 answers