A) Initial Kinetic Energy
= Work done to stop
= (Avg. Force)*(Distance, X)
F = (1/2)(0.00724)*(636)^2/0.0487 m)
= ___ N
B) (Avg speed)*time = Distance
Time = 0.0487 m/318 m/s
= 1.53*10^-4 s
A 7.24 g bullet moving at 636 m/s penetrates a tree to a depth of 4.87 cm. Use energy considerations to find the average frictional force that stops the bullet. Answer in units of N
B) Assuming that the frictional force is constant how much time elapsed between the moment of the bullet entering the tree and moment it stopped? Answer is Seconds
1 answer
1 answer