A 7.00-kg bowling ball moves at 2.15 m/s. How fast must a 2.40-g Ping-Pong ball move so that the two balls have the same kinetic energy?

Answer 1

Ke = .5 m v^2

.5 (7)(2.15)^2 = .5 (.0024) v^2

v^2 = (7)(2.15)^2/.0024