A 7.00 g sample of KCl is dissolved in 81.0 mL of water. The resulting solution is then added to 28.0 mL of a 0.790 M CaCl2(aq) solution. Assuming that the volumes are additive, calculate the concentrations of each ion present in the final solution.

Answer 1

mols KCl = grams/molar mass = ?
mols CaCl2 = M x L = ?

mols K^+ = mols KCl
mols Ca^2+ = mols CaCl2
mols Cl^- = mols KCl + 2*mols CaCl2

Then (K^+) = mols K/L
(Ca^2+) = mols Ca/L
(Cl^-) = mols Cl/L
Note: total volume is 81 mL + 28 mL = ? mL and convert to L.