use this sample problem. Go through it first.
http://www.jiskha.com/display.cgi?id=1273284765
A 6m long uniform ladder which has a mass of 25kg leans with its upper end against a smoorth vertical wall and its lower end on rough horizontal ground. The base of the ladder is 3m from the wall and a man of mass 70kg is two thirds of the way up the ladder.
calculate frictional force between the ladder and the ground
determine the magnitude and direction of the resultant force acting on the base of the ladder
5 answers
??
F=M
70*9.8=686
25*9.8=245
686+245=921
f=931
still don't know about the magnitude
F=M
70*9.8=686
25*9.8=245
686+245=921
f=931
still don't know about the magnitude
magnitude: you have friction force and weight on the ladder base. They are at 90 degrees. Add them
so its 931^2-29.4^2
= sqrt so its 930.5 is the magnitude?
= sqrt so its 930.5 is the magnitude?
i don't think either is right
1 answer