A 69 mL sample of a solution of sulfuric acid is neutralized by 41 mL of a .161 M sodium hydroxide solution. Calculate the molarity of the sulfuric acid solution. Answer in units of mol/L.

Answer 1

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols NaOH = M x L = ?
mols H2SO4 = 1/2 x mols NaOH (Look at the coefficients in the balanced equation.)
Then M H2SO4 = mols H2SO4/L H2SO4 = ?