A 69.5kg football player is gliding across very smooth ice at 2.15m/s . He throws a 0.470kg football straight forward.

Question

What is the player's speed afterward if the ball is thrown at 16.0m/s relative to the ground?

What is the player's speed afterward if the ball is thrown at 16.0m/s relative to the player?

Answer 1

initial momentum forward = (69.5+.47)(2.15)
= 150.4
so
150.4 = 69.5 v + .470*16

in second part
v ball = 2.15 + 16 = 18.15 m/s
150.4 = 69.5 v + .470*18.15

Answer 2

so you would get 2m/s for both however that is not correct

Answer 3

2.05
2.04