The heat gained by the ice cube in melting and heating up to final temperature T equals the heat lost by the original liquid water.
68*(80 + T) = 796*(30 - T)
80 cal/g is the heat of fusion of ice.
Solve for T.
5440 + 68T = 23,880 -796 T
864 T = 18440
T = 21.3 C
A 68-g ice cube at 0°C is placed in 796 g of water at 30°C. What is the final temperature of the mixture?
1 answer