A 67.7 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 1.04 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Answer 1

Lost potential energy
= M*g*(3.11 + 1.04)= M*g*(4.15 m)
= work done against friction
= Fav*(1.04 m)

(There is zero kinetic energy at the beginning of the dive and the greatest underwater depth)

Fav = (4.15/1.04)*M*g
= 734 N

Answer 2

2753.3 J