a. KE = 0.5*M*V^2 = 0.5*66*4.3^2 = 610.2 J. = Energy lost due to friction.
b. M*g = 66 * 9.8 = 646.8 N. = Wt. of runner = Normal(Fn).
Fk = u*Fn = 0.6 * 646.8 = 388.1 N. = Force of kinetic friction.
KE = Fk*d = 610.2
388.1*d = 610.2
d = 1.57 m.
A 66-kg baseball player slides into third base. He starts his slide at a speed of 4.3 m/s and his speed is zero just as he reaches the base. If the coefficient of friction between his clothes and the surface of the baseball infield is 0.60, determine the following.
(a) mechanical energy lost due to friction acting on the player
J
(b) distance he slides
m
2 answers
Consider a situation where a baseball player slides to a stop on level ground. Using
energy considerations, calculate the distance the 65.0 kg baseball player slides, given that
his initial speed is 6.0 m/s and the force of friction against him is a constant 450 N
energy considerations, calculate the distance the 65.0 kg baseball player slides, given that
his initial speed is 6.0 m/s and the force of friction against him is a constant 450 N