Assume total momentum [of thrower + snowball in (a) and catcher plus snowball in (b)] is conserved in both cases.
The phrase "perfectly inelastic" is rather meaningless
A 66.5 kg ice skater moving to the right with a velocity of 2.80 m/s throws a 0.16 kg snowball to the right with a velocity of 20.4 m/s relative to the ground.
(a) What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.
(b) A second skater initially at rest with a mass of 61.00 kg catches the snowball. What is the velocity of the second skater after catching the snowball in a perfectly inelastic collision?
2 answers
1a Conservation of momentum.
original momentum= final momentum
I assume the ice skater was carrying snow with her.
(66.5+.16)2.80=66.5V+.16*20.4
solve for V.
b. initialmomentum= final moentum
.16*20.4=(61.16V)
solve for V
original momentum= final momentum
I assume the ice skater was carrying snow with her.
(66.5+.16)2.80=66.5V+.16*20.4
solve for V.
b. initialmomentum= final moentum
.16*20.4=(61.16V)
solve for V
0 answers