A 66.2 kg person sits on the 5.3 kg sled (slope is on an angle, angle not given). It is to be pulled across the snow with a coefficient of friction equal to 0.12. What horizontal force is required to pill the sled at a constant speed?

Answer 1

Fg=m*g = (66.2kg+5.3kg)*9.8N/kg=700.7 N.
= Force of gravity = Combined wt. of
person and sled.

Ff = u*Fg = 0.12 * 700.7 = 84.1 N. =
Force of friction.

Fx-Ff = m*a
Fx-84.1 = m*0 = 0
Fx = 84.1 N.