A 65kg diver stands still on a tower 10.0m above water.

Answer 1

To solve this problem, we need to find the potential energy of the diver standing on the tower.

The potential energy (PE) is given by the equation: PE = mgh

Where:
m = mass of the diver = 65kg
g = acceleration due to gravity = 9.8 m/s²
h = height of the tower = 10.0m

By substituting the values into the equation, we get:

PE = 65kg × 9.8 m/s² × 10.0m

PE = 6,370 J

Therefore, the potential energy of the diver standing on the tower is 6,370 Joules.