A 65 kg student consumes 2500 Cal each day and stays at the same weight. For three days in a row, while visiting his parents, she eats 3500 Cal and, wanting to keep from gaining weight decides to "work off" the excess by jumping up and down.

Question

A 65 kg student consumes 2500 Cal each day and stays at the same weight. For three days in a row, while visiting his parents, she eats 3500 Cal and, wanting to keep from gaining weight decides to "work off" the excess by jumping up and down. 
With each jump, he accelerates to a speed of 3.2 m/s before leaving the ground.

a) How high will he jump each jump?
b) How many jumps must he do to keep his weight? (body efficiency= 25%)
c) Is this a reasonable way not to gain weight?
d) What other ways can the student keep his weight?

bobpursley · Answer

how high: KE=mgh h= (1/2 * 65*3.2^2 )/(65*9.8)=.52m... jumps=(2500C*.25*1000c/C*4.18J/c )/(1/2*65*3.2^2)=7850

Live · Answer

@bobpursley Which formula did u use to obtain this jumps=(2500C*.25*1000c/C*4.18J/c )/(1/2*65*3.2^2)