A 65-kg skier starts at rest and slides 30 m down a hill inclined at 12∘ relative to the horizontal. Consider the force of friction on the skier to be negligible.

Determine the speed of the skier after sliding 30 m downhill.

1 answer

h = 30*sin12 = 6.24 m.

Vf^2 = Vo^2 + 2g*h = 0 + 19.6*6.24 = 122.3.
Vf = 11.1 m/s.