A 62 kg hiker climbs to the top of a 3700 m-high mountain. The climb is made in 5.0 h starting at an elevation of 2600 m. Calculate the average power output in watts. Calculate the average power output in horsepower.

Answer 1

First you need to calculate the PE needed to make the climb.
U=mgh U=(62*(2600-3700)*9.8)
This value is energy or work denoted as a Joule. A Watt= Joule/Seconds
So simply take your joules and divide it by the time the trip took. Convert your 5hr to seconds so...

W=(62*(2600-3700)*9.8)/(5*3600)

easy way to find HP is 1W=0.00134102209HP or

HP=(62*(2600-3700)*9.8)/(5*3600)*0.00134102209