A 62% by mass of aqueous solution. of acid has specific gravity 1.8 . This solution is diluted such that. the specific gravity of solution become 1.2 fine find Percent by weight. of acid in this solution.

Answer 1

To solve this problem, we first need to determine the mass of the acid in the original aqueous solution.

Let's assume we have a 100g sample of the original aqueous solution.

Given that the specific gravity of the solution is 1.8, we know that 1 liter of the solution weighs 1.8 kg or 1800g.

Since 62% of the solution is acid by mass, the mass of acid in the solution is 0.62 * 100g = 62g.

Now, let's determine the volume of the original solution. To do this, we'll use the specific gravity and the known mass of 100g.

The volume of 100g of the original solution is 100g / (1.8g/mL) = 55.56 mL.

Now, let's dilute this solution in such a way that the specific gravity becomes 1.2.

Given the specific gravity of 1.2 and the volume of the original solution (55.56 mL), we can determine the new mass of the diluted solution.

Let's assume the new mass of the diluted solution is x g.

The mass of the acid in the diluted solution will still be 62g.

So, the new volume of the diluted solution can be calculated using the specific gravity and the new mass:

x g / (1.2g/mL) = 55.56 mL

x = 55.56 mL * 1.2g/mL = 66.67 g

Therefore, the percent by weight of the acid in the diluted solution is:

(62g / 66.67g) * 100% = 93%