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A 6110-kg bus traveling at 20.0 m/s can be stopped in 24.0 s by gently applying the brakes. If the
driver slams on the brakes, the bus stops in 3.90 s. What is the average force exerted on the bus in both
these stops?
3 answers
(Avg. force)*(time) = (momentum change)
= M * Vo
Solve for the average force.
= M * Vo
Solve for the average force.
hjbk
2 answers