A 60m long bridge has an opening in the middle and both sides open up to let boats pass underneath. The two parts of the bridge floor rise up to a height of 18 m. Through what angle do they move?
2 answers
sin(Θ) = 18 / 30
Imagine the bridge to be a huge right angled triangle . It it rises by 18 m then the this height is the opposite and the length of the bridge is the hypotenuse . Now, apply sin theta ( hope , u know this ) using the SOH CAH TOA rule we get that sin theta is 18 / 30 further simplifying we get 3/5 . Now, if u enter arc sin of 3/5 in your calculator you will approximately get 36.87 or 37 degrees as the answer . That's it .......
7 answers