a 60kg man is on a steadily rotating Ferris wheel. the man is standing on a bathroom scale and the scale reads 45kg at the top of the wheel. take g=10m/s^2
(a) what does the scale read when the man is at the bottom of the wheel?
(b)what does the scale read when the man is level with the hub of the wheel going up? assume their is sufficient friction that the man's feet do not slide off the scale?
(c) what co-efficient of friction is needed to keep the man's feet on the scale in (b)?
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i was able to figure out the acceleration which is -2.5 m/s^2..for part A the answer is 75kg however i don't understand how to get that answer as well as the other two parts...any help would be appreciated :)
2 answers
b) the man is vertical, his weight is mg, centripetal force does not add to weight. However, to keep him accelerating inward, fricion must be m*v^2/r
thita ka beyapk man
1 answer