a 60 kg skier with an initial velocity of 12 m/s coasts up a hill. at the top of the hill, the skier is traveling at 9.75 m/s. Assuming there is no friction force in the skis, how high was the hill

A) 7.35 m

B) 0.25 m

C) 10 m

D) 2.5 m

2 answers

m V^2 - m v^2 = 2 m g h

12^2 - 9.75^2 = 2 * 9.8 * h
Okay so

GPE = KE (Gravitational Potential Energy = Kinetic Energy)
GPE = mgh (Gravitational Potential Energy = mass x gravity x height)

KE = 1/2mv^2
KE = 1/2(60) * (12)^2
KE = 4320

KE before hill: 4320 J

KE = 1/2(60) * (9.75)^2
KE = 2851.875

KE after hill: 2851.875 J

4320 - 2851.875 = 1468.125

1468.125 = mgh
1468.125 = (60)(9.81)(h)
1468.125/(60)(9.81) = h
1468.125/588.6 = h
2.494 = h

The answer is D. 2.5 m
c: