A 60.0 kg person rides in elevator while standing on a scale. The elevator has an acceleration 2.00 m/s^2 upward. What is the reading on the scale?

Answer 1

m=60.0
a=2.00
FN-mg=ma
FN=ma + mg
FN=m(a+g)
FN=60(2.00+9.8)
Answer 708N

Answer 2

It's correct

Answer 3

If you need the scale reading in kg just divide the force by g