a 60.0 g sample of chromium at 82.0 degrees celsius was place in 80.0 g of water. Assume there is no loss of heat to the environment. What is the final temperature of the water and chromium? The initial water temperature was 24.0 degrees celsius

Answer 1

heat lost by Cr + heat gained by H2O = 0

[mass Cr x specific heat Cr x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Post your work if you get stuck.