A 6.110 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is μs = 0.455 and the coefficient of kinetic friction is μk = 0.255. At time t = 0, a force F = 16.8 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times:

Answer 1

At time t = 0: The force of friction applied to the block by the table is 7.6 N (Ff = μs * F = 0.455 * 16.8 = 7.6 N).

At time t = 1 second: The force of friction applied to the block by the table is 6.2 N (Ff = μk * F = 0.255 * 16.8 = 6.2 N).