A 6.0kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant horizontal force of 12 N. Find the speed of the block after it has moved 3.0 m.

Answer 1

a = F/m = 12 N / 6 kg = 2 m/s^2
v = a t = 2 t
x = (1/2) a t^2 = 1 t^2
so t^2 = 3
t = sqrt 3
v = 2 t = 2 sqrt 3

Answer 2

or, v^2 = 2as = 2*2*3 = 12
v = 2√3

Answer 3

Q1