a 6.0 L vessel contained 0.0222 mol of phosphorus trichloride, 0.0189 mol phosphorus pentachloride and 0.1044 mol of chlorine at 230 degrees celsius in an equilibrium mixture. calculate the equilibrium constant kc and kp for the reaction. PCl3 +Cl2-PCL5

Answer 1

(PCl3) = mols/L = 0.0222/6L = ? and I'll call this w.
(Cl2) = mols/L = ? = y
(PCl5) = mols/L = ? = z
........... PCl3 + Cl2 ---> PCL5
Eq....... w.........y.............z

Write the expression for the equilibrium constant, Kc, plug in the numbers and calculate Kc.
Then Kp = Kc(RT)^delta n

Post your work if you get stuck.