a 6.0 kW electric oven is connected to a fuse box by a cable of resistance 0.25 ohms. when the cooker is switched on at full power, a current of 26 A passes through it.

Calculate the potential difference between the two ends of the cable and the power wasted in it because of the heating effect of the current.
What %age of the power supplied to the cable is wasted?

1 answer

power wasted: I^2 * resistance

Assuming the actual power used by the oven is 6kw, then voltage=6000/26 volts

percent power wasted= powerwasted/(6kw+powerwasted) * 100