If=230/115 equals 2A
Ia is 18-2 equals 16A
Equate using KVL
230=[Ia(st) (0.25+Rst) + 3]
Rst = 9.2083 ohms
A 5hp 230volt shunt motor takes 18 amp when operating at full load. The Shunt-field resistance is 115ohms and the armature resistance is 0.25 ohm. calculate the value of the starter resistor if the armature current is limited to 1.5 times the rated value at the starting instant. (assume a 3-volt brush drop.)
the answer is 9.2 ohms.
I just can't get it. pls help me on this. thanks in advance!
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