A 56-kg rollerblader skates across a skating rink floor. The graph below shows the net external force component F cos è along the displacement as a function of the magnitude of the displacement d. Determine the Following:

(a) work done by the net force component F cos è acting on the rollerblader as he moves from 0 to 5.0 m


(b) work done by the net force component F cos è acting on the rollerblader from 5.0 m to 10.0 m

1 answer

Unfortunately, I cannot see the graph you are referring to. However, I can still provide the formulas and general approach to solve problems like these.

The work done by a force is given by the equation:

W = F * d * cos(θ)

Here, W is the work done, F is the force, d is the displacement, and θ is the angle between the force and displacement vectors. Since the graph already provides F * cos(θ), all that is required is to find the area under the curve of this graph within the desired displacement range.

(a) To find the work done by the net force component F * cos(θ) acting on the rollerblader as he moves from 0 to 5.0 m, you need to find the area under the curve of the graph from 0 to 5.0 m. You can do this by approximating with rectangles, trapezoids, or by using calculus, depending on the shape of the curve.

(b) Similarly, to find the work done by the net force component F * cos(θ) acting on the rollerblader from 5.0 m to 10.0 m, you need to find the area under the curve of the graph from 5.0 m to 10.0 m. Again, you can do this by approximating with rectangles, trapezoids, or by using calculus, depending on the shape of the curve.