A 55.3 kg skier is moving at 14.9 m/s on a frictionless horizontal, snow covered plateau when she encounters a rough patch 1.7 m long. The coefficient of kinetic friction between this patch and her skis is 0.27. After crossing the rough patch, what is the speed of the skier in ms-1 ? g=9.8ms-2

Answer 1

KE initial- Work lost to Friction = KE final
Ff = mu mg = .27*55.3*9.8
so
1/2 55.3 14.9^2 - Ff(1.7) = 1/2 55.3 vf^2
solve for vf

Answer 2

thanks:)