F = 543 - 473 = 79 N down on the student
mass of student = 543/g
a = F/m = 79 / (543/9.81)
= 1.43 m/s^2 down
A 543-N physics student stands on a bathroom scale in an 805-kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 473 N
A) Find the magnitude of the acceleration of the elevator.
2 answers
Not correct but thanks anyway