A 52.0 g ball of copper has a net charge of 2.1 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

Answer 1

number electrons removed=2.1microC*/charge on one electron

original number elecrons:

number moles*avagrado's number*29

fraction=removed/original