Ac = v^2/r = 36/2 = 18 m/s^2
m
F = M Ac = 51 *18 Newtons
weight = 51 * 9.81 Newtons
almost 2 g
A 51kg person on a merry-go-round is traveling in a circle with a radius of 2 m at a speed of 6 m/s
A) What acceleration does the person experience?
B) What is the net horizontal force?
C) How does it compare with the person's weight?
2 answers
acceleration= v^2/r
force=mass*acceleration
weight=51*9.8 N
force=mass*acceleration
weight=51*9.8 N
0 answers