A 515 cm3 block of aluminum (Density = 2.7 g/cm3) is lowered carefully into a completely full beaker of water. What is the weight of the water, in newtons, that spills out of the beaker?

Answer 1

assuming that the beaker is of a size and shape to completely contain the block, an amount of water equal to the block's volume will be displaced.

515cm^3 water = 515 g = .515kg
weight = 9.81 * .515