A 51.5-kg skater is traveling due east at a speed of 2.70 m/s. A 69.5-kg skater is moving due south at a speed of 7.50 m/s. They collide and hold on to each other after the collision, managing to move off at an angle θ south of east, with a speed of vf. Find the following.

Answer 1

initial momentum=final momentum
51.5*2.7E+69.5*7.5=(51.5+69.5)V

so there are a number of ways to do this, because of the right angles,

(51.5+69.5)V= sqrt((51.5*2.7)^2+(69.5*7.5)^2)

solve for V,
it is at an angle theta measured E of S as
arctan((51.5*2.7)/(69.5*7.5) )