at one meter from the hinge at the wall you have 491 N down
at 1.5 meters from the wall you have T sin 30 up
moments about hinge at wall yield:
(T sin 30) * 1.5 = 491 * 1
T (1/2)(3/2) = 491
T = 491 * 4/3
A 50kg sign for a local business is hung from a bar which meets a wall at right angles as shown in figure 1. The bar is 1.5 meters long, and it's mass may be neglected. The center of mass of th sign is 1.0 meters from the wall (but .50 meters from the tip of the cable) as indicated. A cable (we assume massless) extends from the end of the rod to the wall. Assume the rod is attached to the wall with a joint which permits the rod to rotate freely. The angle between the cable and bar is 30 degrees. What is the tension in the cable.
I know to get the mass you do MG which is 491N I am struggling on what to do since the mass is not hanging on the end but between two different lengths, how do I use these two lengths to solve my answer? I believe the answer is 650N
1 answer
1 answer