c. THat energy had to come from GPE.
mgh=8.486 solve for h, that is the h above the final position of the spring. So you need to subtract the .184
A 506 g block is released from rest at height h0 above a vertical spring with spring constant k = 500 N/m and negligible mass. The block sticks to the spring and momentarily stops after compressing the spring 18.4 cm. How much work is done (a) by the block on the spring and (b) by the spring on the block? (c) What is the value of h0? (d) If the block were released from height 5h0 above the spring, what would be the maximum compression of the spring?
a) I used Ws = -[.5kxf^2 - .5kxi^2] and got 8.464 J
b) Is just the negative of that so -8.464 J
*For both a and b my reference angle was the compressed spring bottomed out. So my initial value was 0 and final value was .184*
c) and d) I don't really know how to go about finding the initial height. How would I do this?
4 answers
So tbe work done by the spring is the Potential Energy = mgh?
I get 1.7069 m.
For part d) How would you find the compression of the spring at h0 = 8.5345 m?
I get 1.7069 m.
For part d) How would you find the compression of the spring at h0 = 8.5345 m?
I think I screwed up somewhere because my values aren't correct. Am I supposed to set it up like mg(h-.184) = 8.464?
I just tried 8.464 = mg(h-.184) and my answer for the height was still wrong. What am I doing wrong here ...
I should add for part d) I have it set up so that mgh = .5kx^2 to find the max compression at 5h. I think both of these are right yet my answers still ring up as wrong.
I should add for part d) I have it set up so that mgh = .5kx^2 to find the max compression at 5h. I think both of these are right yet my answers still ring up as wrong.