ℰ=-dΦ/dt=-d(NBAcosωt)/dt=
=NBAωsinωt =
=500•0.05•0.05•20•sin30° =12.5 V
A 500-turn circular coil with an area of 0.050 0 m2 is mounted on a rotating frame that turns at a rate of 20.0 rad/s in the presence of a 0.050 0-T uniform magnetic field that is perpendicular to the axis of rotation. What is the instantaneous emf in the coil at the moment that the normal to its plane is at a 30.0 angle to the field? answer
1 answer