the moment of inertia is mr^2 .
Torque=thrust*radiusrotation=I*angacceleration
solve for angular acceleration.
Then, wf^2=2*a*displacementinradians
tension= m*w^2*r
A 500 g steel block
rotates on a steel table while attached to a 2.0-m-long massless rod. Compressed air fed through the rod is ejected from a Inozzle on the back of the block, exerting a thrust force of 3.5 N. The nozzle is 70^\circ from the radial line, as shown in the figure . The block starts from rest.
a)What is the block's angular velocity after 10 rev?
b)What is the tension in the rod after 10 rev?
2 answers
Tough one, cutie.
1 answer