I wonder what kind of glass, and what was the initial temperature of the copper. All that matters.
Sum the heats gained, and set to zero (one will be negative)
heat gained glass+heatgainedwater+heatgainedCu=0
and each of those will be equal to
mass*specificheatformaterial*(Tf-Ti)
A 500 g glass beaker is in thermal equilibrium with 100 ml of 20 Degrees celsius water in it. If a 5 g sample of copper is placed into the water and the system is allowed to come into thermal equilibrium, what will the final temperature of the system be? (assuming no heat loss to the air)
2 answers
is it possible to solve without the initial temperature of the copper?