A 50 N force is applied to the end of a 30 cm wrench and makes an angle of 30 degrees with the handle of the wrench. What is the Torque on the bolt at the other end of the wrench? What direction does the Torque act? What is the Maximum and Minimum Torques and how are these accomplished?
Does the max occur at 90 degrees and the min occurs at 0 degrees?
I can't figure out the other answers.
Thanks
3 answers
You might have to wait till a physics tutor comes on line.
The torque in the configuration you described is the lever arm length multiplied by the component of the force normal to the lever arm. That would be
50 N * 0.3 m * sin30 = 7.5 Newton meter..
With the same force and lever arm, the max torque would occur when the angle is 90 degrees. Your intuition is correct.
50 N * 0.3 m * sin30 = 7.5 Newton meter..
With the same force and lever arm, the max torque would occur when the angle is 90 degrees. Your intuition is correct.
What is the torque on a bolt applied with a wrench that has a lever arm of 7.5 m with a force of 90 N?
3 answers