A 50 g lunch pail is lifted up 500 m. If the work required to do this was 1450 J, what's the acceleration?

Question

W= mad
1450 = (0.05 kg)(a)(500m)
1450 = 250a
5.8 m/s^2 = a

If a 750 g mass is accelerated at a rate of 11.0 m/s^2 for a distance of 3.0 m, how much work was done?

W = mad
W = (0.75kg)(11.0m/s^2)(3.0m)
W = 24.75 J
W= 24.8 J

Thanks!

Answer 1

but you forgot the work done against gravity
m g * 500 = .05 * 9.81 * 500 = 245 J

1450 - 245 = 1204 J
so
1204 = .05 * a * 500
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The second one looks ok

Answer 2

Thanks!