The first step is to convert the volume of the solution in the radiator to liters.
6.4gal x 3.785L = 24.2266L
Determine the mass of the water in the solution using the 50/50 blend (by volume), and the density of water.
24.2266/2=12.1133L
Water: .998g/molx1000L=998g/L
998g/Lx12.1133L=12089.0734g~12.0Kg
glycol =^ molae mass= 62.0674mol/g
1.11g/ml=1110g/L x 12.1133L = 13445.763g/62.06 = 216.63 mol.
solve for m= mole/Kg
Fnal part.
T=(Kb)(m)
=.512x17.9
=9.1648 + 100 degrees
T= 109.17
=.512
A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile\'s engine cooling system. If your car\'s cooling system holds 4.20 gallons, what is the boiling point of the solution? Make the following assumptions in your calculation; at normal filling conditions, the densities of engine coolant and water are 1.11 g/mL and 0.998 g/mL respectively. Assume that the engine coolant is pure ethylene glycol (HOCH2CH2OH), which is non-ionizing and non-volatile, and that the pressure remains constant at 1.00 atm. Also, you\'ll need to look up the boiling-point elevation constant for water.
2 answers
Convert Gallons to Liters. 1 Gallon = 3.785L
Convert Liters to mL (since density is in mL). 1L = 1000mL
Divide Volume you get in half since the solution is a 50/50 blend by volume.
Multiple each density (water and ethyl gylcol) by their volume(which is the same for both, just half the total volume). this gives you the mass for each.
Convert mass of ethyl glycol to moles using molar mass 62.07g/mole
Convert mass of H2O from grams to Kg. 1000 gram = 1kg
now all these steps were to give you the moles of the solute (ethyl glycol) and the mass in kg of the solvent (H2O) so you can find the molality
so divide the moles of ethyl glycol by kg of H20
now to find the increase in boilig point, use this equation: DeltaT= i*m*Kb
we already found m, the molality, i=1 since the solute is molecular, and the Kb for water is O.512
so plug and chuck and you should be good.
last step is to add the delta T to the boiling point of water (100 degrees C) and that's your final answer.
Chem can be tough but you got this! keep your head up King/Queen!
Convert Liters to mL (since density is in mL). 1L = 1000mL
Divide Volume you get in half since the solution is a 50/50 blend by volume.
Multiple each density (water and ethyl gylcol) by their volume(which is the same for both, just half the total volume). this gives you the mass for each.
Convert mass of ethyl glycol to moles using molar mass 62.07g/mole
Convert mass of H2O from grams to Kg. 1000 gram = 1kg
now all these steps were to give you the moles of the solute (ethyl glycol) and the mass in kg of the solvent (H2O) so you can find the molality
so divide the moles of ethyl glycol by kg of H20
now to find the increase in boilig point, use this equation: DeltaT= i*m*Kb
we already found m, the molality, i=1 since the solute is molecular, and the Kb for water is O.512
so plug and chuck and you should be good.
last step is to add the delta T to the boiling point of water (100 degrees C) and that's your final answer.
Chem can be tough but you got this! keep your head up King/Queen!
2 answers