A 50.0 mL sample of 6.0 M HCL is dulited to 200.0 mL. What is the new concentration of the acid?

Answer 1

for this type of problem use

M1V1=M2V2

(provided that the M and V are in the same units no conversion is needed)

50.0 ml x 6.0 M = 200.0 ml x M2

so M2=50.0 ml x 6.0 M/200.0 ml