Asked by Sa ndra
A 50.0 mL sample of 6.0 M HCL is dulited to 200.0 mL. What is the new concentration of the acid?
Answers
Answered by
Dr Russ
for this type of problem use
M1V1=M2V2
(provided that the M and V are in the same units no conversion is needed)
50.0 ml x 6.0 M = 200.0 ml x M2
so M2=50.0 ml x 6.0 M/200.0 ml
M1V1=M2V2
(provided that the M and V are in the same units no conversion is needed)
50.0 ml x 6.0 M = 200.0 ml x M2
so M2=50.0 ml x 6.0 M/200.0 ml
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.